(12n^3+12n^2+2n)/4n^3

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Solution for (12n^3+12n^2+2n)/4n^3 equation: 


n in (-oo:+oo)

n^3*((12*n^3+12*n^2+2*n)/4) = 0

(n^3*(12*n^3+12*n^2+2*n))/4 = 0

12*n^3+12*n^2+2*n = 0

2*n*(6*n^2+6*n+1) = 0

6*n^2+6*n+1 = 0

DELTA = 6^2-(1*4*6)

DELTA = 12

DELTA > 0

n = (12^(1/2)-6)/(2*6) or n = (-12^(1/2)-6)/(2*6)

n = (2*3^(1/2)-6)/12 or n = (-2*3^(1/2)-6)/12

2*n*(n-((-2*3^(1/2)-6)/12))*(n-((2*3^(1/2)-6)/12)) = 0

(2*n*n^3*(n-((-2*3^(1/2)-6)/12))*(n-((2*3^(1/2)-6)/12)))/4 = 0

( 2*n )

2*n = 0 // : 2

n = 0

( n-((-2*3^(1/2)-6)/12) )

n-((-2*3^(1/2)-6)/12) = 0 // + (-2*3^(1/2)-6)/12

n = (-2*3^(1/2)-6)/12

( n-((2*3^(1/2)-6)/12) )

n-((2*3^(1/2)-6)/12) = 0 // + (2*3^(1/2)-6)/12

n = (2*3^(1/2)-6)/12

( n^3 )

1*n^3 = 0 // : 1

n^3 = 0

n = 0

n in { 0, (-2*3^(1/2)-6)/12, (2*3^(1/2)-6)/12, 0 }

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